Lector enojado con el ex arbitro Castri función q cumple el titulo​ porfa va estoy en examen

4x^2-6x+2=0

2(2x^2-3x+1)=0

2x. -1

x. -1

2x(-1)+x(-1)= -2x-x=-3x

2(2x-1)(x-1)=0

(2x-1)(x-1)=0

Producto de dos factores igual a 0, cada uno debe ser igual a 0:

2x-1=0 v x-1=0

x=1/2 v x=1

Explicación paso a paso:

Podemos encontrar las raíces de la función f(x) = 4x^2 - 6x + 2 utilizando la fórmula general de las raíces de una ecuación cuadrática:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

Donde a = 4, b = -6 y c = 2. Sustituyendo en la fórmula, obtenemos:

x = (-(-6) ± sqrt((-6)^2 - 4(4)(2))) / 2(4)

x = (6 ± sqrt(36 - 32)) / 8

x = (6 ± sqrt(4)) / 8

Por lo tanto, las dos raíces de la función son:

x1 = (6 + 2) / 8 = 1

x2 = (6 - 2) / 8 = 0.5

Entonces, las raíces de la función son x = 1 y x = 0.5.

Explicación:

Comparativo:

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Superlativo:

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Respuesta:

Factorizamos en sus factores primos.

16 l 2.

8 l 2.

4 l 2.

2 l 2.

150 | 2.

75 | 3.

25 | 5.

5 | 5.

Factores primos de 150= 2* 3* 5²

75

tiene factores de

3

y

25

.

2

⋅

2

⋅

2

⋅

2

⋅

3

⋅

25

RESPUESTAS:

Rtas:

16= dos elevada a la cuarta

150= 2×3×cinco elevada al cuadrado

1200= dos elevada a la cuarta×3×cinco elevada al cuadrado.

EXPLICACIÓN PASO A PASO:

Solución Solución 2. Solución 3

16 | 2 150 | 2 1200 | 2

8 | 2 75 | 3 600 | 2

4 | 2 25 | 5 300 | 2

2 | 2 5 | 5 150 | 2

1 | 1 | 75 | 3

25 | 5

5 | 5

1 |

16= 2**** 150= 2×3×5** 1200= 2**×3×5**